**Download Big Ideas Math Answers Grade 6 Chapter 6 Equations P****df** for free of cost. If you are browsing for various questions of equations, then here is the one-stop solution. Know the benefit of referring to Big Ideas Math Book 6th Grade Answer Key Chapter 6 Equations. You can learn the tips and simple methods to solve all the problems. With the below-given material, it acts as a guide to get better marks in the exam. Get a free step-by-step solution from this ultimate guide ie., BIM 6th Grade Solutions Ch 6 Equations. Check the below sections to get various details and information.

## Big Ideas Math Book 6th Grade Answer Key Chapter 6 Equations

It is necessary for the candidates to understand the concept in maths. Concept is important than scoring marks in the exam. Therefore relate the questions with real-time problems and understand the concept in depth. With all the factors into consideration, * BIM 6th Grade Answer Key or Equations Pdf* is prepared. Click on the links in the next sections and start practicing the problems. Follow the various topics, Steam videos and Solved problems available in BIM Equations book and pdf.

**Performance Task**

**Lesson 1: Writing Equations in One Variable**

- Lesson 6.1 Writing Equations in One Variable
- Writing Equations in One Variable Homework & Practice 6.1

**Lesson: 2 Solving Equations Using Addition or Subtraction**

- Lesson 6.2 Solving Equations Using Addition or Subtraction
- Solving Equations Using Addition or Subtraction Homework & Practice 6.2

**Lesson: 3 Solving Equations Using Multiplication or Division**

- Lesson 6.3 Solving Equations Using Multiplication or Division
- Solving Equations Using Multiplication or Division Homework & Practice 6.3

**Lesson: 4 Writing Equations in Two Variables**

- Lesson 6.4 Writing Equations in Two Variables
- Writing Equations in Two Variables Homework & Practice 6.4

**Chapter 6 – Equations**

- Equations Connecting Concepts
- Equations Chapter Review
- Equations Cumulative Practice
- Equations Practice Test

### Equations STEAM Video/ Performance Task

**STEAM Video**

Rock Climbing

Equations can be used to solve many different kinds of problems in real life, such as estimating the amount of time it will take to climb a rock wall. Can you think of any other real-life situations where equations are useful?

In rock climbing, a pitch is a section of a climbing route between two anchor points. Watch the STEAM Video “Rock Climbing.”en answer the following questions.

1. How can you use pitches to estimate the amount of time it will take to climb a rock wall?

2. Are there any other methods you could use to estimate the amount of time it will take to climb a rock wall? Explain.

3. You know two of the three pieces of information below. Explain how you can find the missing piece of information.

Average climbing speed

Height of rock wall

Time to complete climb

**Performance Task**

Planning the Climb

After completing this chapter, you will be able to use the concepts you learned to answer the questions in the STEAM Video Performance Task. You will be given information about two rock-climbing routes.

Route 1: 500 feet, 125 feet per pitch

Route 2: 1200 feet, 8 pitch

You will find the average speed of the climbers on Route 1 and the amount of time it takes to complete Route 2. Will the average speed of the climbers on Route 1 provide accurate predictions for the amount of time it takes to climb other routes? Explain why or why not.

### Equations Getting Ready for Chapter 6

**Chapter Exploration**

Work with a partner. Every equation that has an unknown variable can be written as a question. Write a question that represents the equation. Then answer the question.

Answer:

Work with a partner. Write an equation that represents the question. Then answer the question.

Answer:

**Vocabulary**

The following vocabulary terms are defined in this chapter. Think about what each term might mean and record your thoughts.

equation

independent variable

inverse operations

dependent variable

equation in two variables.

### Lesson 6.1 Writing Equations in One Variable

**EXPLORATION 1**

Writing Equations

Work with a partner. Customers order sandwiches at a cafe from the menu board shown.

a. The equation 6.75x =20.25 represents the purchase of one customer from the menu board. What does the equation tell you about the purchase? What cannot be determined from the equation?

b. The four customers in the table buy multiple sandwiches of the same type. For each customer, write an equation that represents the situation. Then determine how many sandwiches each customer buys. Explain your reasoning.

Answer:

An equation

is a mathematical sentence that uses an equal sign, =, to show that two expressions are equal.

Expressions

4 + 8

x + 8

Equations

4 + 8 = 12

x + 8 = 12

To write a word sentence as an equation, look for key words or phrases such as is, the same as, or equals to determine where to place the equal sign.

**Try It**

**Write the word sentence as an equation.**

Question 1.

9 less than a number be equals 2.

Answer: 9-x=2

Explanation:

We have to write the equation for the word sentence

The phrase “less than” indicates -.

let the number be x.

9 – x = 2

Question 2.

The product of a number g and 5 is 30.

Answer: 5 × g=30

Explanation:

We have to write the equation for the word sentence

The phrase “product” indicates ‘×’

g × 5 = 30

Question 3.

A number k increased by 10 is the same as 24.

Answer: k + 10 = 24

Explanation:

We have to write the equation for the word sentence

The phrase “increased” indicates ‘+’

The equation is k + 10 = 24

Question 4.

The quotient of a number q and 4 is 12.

Answer: q ÷ 4 = 12

Explanation:

We have to write the equation for the word sentence

The phrase quotient indicates ‘÷’

The equation is q ÷ 4 = 12

Question 5.

2\(\frac{1}{2}\) is the same as the sum of a number w and \(\frac{1}{2}\).

Answer: 2 \(\frac{1}{2}\) = w + \(\frac{1}{2}\)

Explanation:

We have to write the equation for the word sentence

The phrase sum indicates ‘+’

The equation is 2 \(\frac{1}{2}\) = w + \(\frac{1}{2}\)

Question 6.

**WHAT IF?**

Each server decorates one table. Which equation can you use to find c?

Answer: We can use the multiplication equation to find c.

**Self-Assessment for Concepts & Skills**

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.

**VOCABULARY**

How are expressions and equations different?

Answer: An expression is a number, a variable, or a combination of numbers and variables and operation symbols. An equation is made up of two expressions connected by an equal sign.

Question 8.

**DIFFERENT WORDS, SAME QUESTION**

Which is different? Write “both” equations.

Answer: n-4=8

4<8

Question 9.

**OPEN-ENDED**

Write a word sentence for the equation 28 −n= 5.

Answer: 28 less than a number n is equals to 5.

Question 10.

**WRITING**

You purchase x items for $4 each. Explain how the variable in the expression 4x and the variable in the equation 4x= 20 are similar. Explain how they are different.

Answer:

You purchase x items for $4 each

4x = 20

x = 20/4

x = 5

Question 11.

After four rounds, 74 teams are eliminated from a robotics competition. There are 18 teams remaining. Write and solve an equation to find the number of teams that started the competition.

Answer:

Given,

After four rounds, 74 teams are eliminated from a robotics competition. There are 18 teams remaining.

Let x be 74 teams

let y be 18 teams

The equation would be

x + y = 92

74 + 18 = 92

Thus the total number of teams are 92.

Question 12.

The mass of the blue copper sulfate crystal is two-thirds the mass of the red fluorite crystal. Write an equation you can use to find the mass (in grams) of the blue copper sulfate crystal.

Answer: blue copper sulfate crystal = 2/3 (red fluorite crystal)

Question 13.

**DIG DEEPER!**

You print photographs from a vacation. Find the number of photographs you can print for $3.60.

Answer: We can print 15 photographs for $3.60

Explanation:

Cost of each print = $0.24

The total cost for photographs is $3.60

3.60/0.24 = 15

Thus We can print 15 photographs for $3.60

### Writing Equations in One Variable Homework & Practice 6.1

**Review & Refresh**

**Factor the expression using the GCF.**

Question 1.

6 + 27

Answer: 3 (2 + 9)

Explanation:

Given the expression 6 + 27

Take 3 as the common factor

3(2 + 9)

Question 2.

9w + 72

Answer: 9(w + 8)

Explanation:

Given the expression 9w + 72

Take 9 as the common factor

9w + 72 = 9(w + 8)

Question 3.

42 + 24n

Answer: 6(7 + 4n)

Explanation:

Given the expression 42 + 24n

Take 6 as the common factor

42 + 24n = 6(7 + 4n)

Question 4.

18h + 30k

Answer: 6(3h + 5k)

Explanation:

Given the expression 18h + 30k

Take 6 as the common factor

18h + 30k = 6(3h + 5k)

Question 5.

Which number is not equal to 225%?

A. 2\(\frac{1}{4}\)

B. \(\frac{9}{4}\)

C. \(\frac{50}{40}\)

D. \(\frac{45}{20}\)

Answer: C

225% is not equal to \(\frac{50}{40}\)

**Evaluate the expression when a = 7.**

Question 6.

6 + a

Answer: 13

Explanation:

Given the expression 6 + a

where a = 7

Substitute the value of a in the expression

6 + 7 = 13

Question 7.

a – 4

Answer: 3

Explanation:

Given the expression a – 4

where a = 7

Substitute the value of a in the expression

a – 4

7 – 4 = 3

Question 8.

4a

Answer: 28

Explanation:

Given the expression 4a

where a = 7

Substitute the value of a in the expression

4 × 7 = 28

Question 9.

\(\frac{35}{a}\)

Answer: 5

Explanation:

Given the expression \(\frac{35}{a}\)

where a = 7

Substitute the value of a in the expression

\(\frac{35}{7}\) = 5

**Find the perimeter of the rectangle.**

Question 10.

Answer:

l = 8 ft

Area = 40 sq ft

We know that,

Area of rectangle = l × w

40 sq. ft = 8 ft × w

w = 40/8 = 5 ft

Thus the width of the above rectangle is 5 ft.

Question 11.

Answer:

l = 13 cm

w = ?

A = 52 sq. cm

We know that,

Area of rectangle = l × w

52 sq. cm = 13 cm × w

w = 52/13

w = 4 cm

Thus the width of the above rectangle is 4 cm.

Question 12.

Answer:

A = 224 sq. miles

l = 14 miles

We know that,

Area of rectangle = l × w

224 sq. miles = 14 × w

w = 224/14

w = 16 miles

Thus the width of the above figure is 16 miles.

**Concepts, Skills, & Problem Solving**

**WRITING EQUATIONS** A roast beef sandwich costs $6.75. A customer buys multiple roast beef sandwiches. Write an equation that represents the situation. Then determine how many sandwiches the customer buys. (See Exploration 1, p. 245.)

Question 13.

Answer:

Given,

A roast beef sandwich costs $6.75.

Amount used for payment = $50.

Change Received = $16.25

The total number of sandwich the customer buys = 5

Question 14.

Answer:

Given,

A roast beef sandwich costs $6.75.

Amount used for payment = $80.

Change Received = $19.25

Amount used for payment – Change Received

= $ 80 – $19.25

= $60.75

1 sandwich = $6.75

The total number of sandwich the customer buys = 9

**WRITING EQUATIONS** Write the word sentence as an equation.

Question 15.

A number y decreased by 9 is 8.

Answer: y – 9 = 8

Explanation:

We have to write the word sentence in the equation form.

y – 9 = 8

Question 16.

The sum of a number x and 4 equals 12.

Answer: x + 4 = 12

Explanation:

We have to write the word sentence in the equation form.

x + 4 = 12

Question 17.

9 times a number b is 36.

Answer: 9b = 36

Explanation:

We have to write the word sentence in the equation form.

The phrase times indicates ‘×’

The equation would be 9b = 36

Question 18.

A number w divided by 5 equals 6.

Answer: w ÷ 5 = 6

Explanation:

We have to write the word sentence in the equation form.

The phrase divided by indicates ‘÷’

The equation would be w ÷ 5 = 6

Question 19.

54 equals 9 more than a number t.

Answer: 54 = 9 + t

Explanation:

We have to write the word sentence in the equation form.

The phrase more than indicates ‘+’

The equation would be 54 = 9 + t

Question 20.

5 is one-fourth of a number c.

Answer: 5 = 1/4 c

Explanation:

We have to write the word sentence in the equation form.

The phrase of indicates ‘×’

The equation would be 5 = 1/4 c

Question 21.

9.5 less than a number n equals 27.

Answer: 9.5 – n = 27

Explanation:

We have to write the word sentence in the equation form.

The phrase less than indicates ‘-‘

The equation would be 9.5 – n = 27

Question 22.

11\(\frac{3}{4}\) is the quotient of a number y and 6\(\frac{1}{4}\).

Answer: 11\(\frac{3}{4}\) = y ÷ 6\(\frac{1}{4}\)

Explanation:

We have to write the word sentence in the equation form.

The phrase quotient indicates ‘÷’

The equation would be 11\(\frac{3}{4}\) = y ÷ 6\(\frac{1}{4}\)

Question 23.

**YOU BE THE TEACHER**

Your friend writes the word sentence as an equation. Is your friend correct? Explain your reasoning.

Answer:

Given the word sentence, 5 less than a number n is 12.

Question 24.

**MODELING REAL LIFE**

Students and faculty raise $6042 for band uniforms. The faculty raised $1780. Write an equation you can use to find the amount a (in dollars) the students raised.

Answer:

Given,

Students and faculty raise $6042 for band uniforms (x).

The faculty raised $1780 (y)

The students raised be z

z = x – y

z = 6042 – 1780

z = 4262

Question 25.

**MODELING REAL LIFE**

You hit a golf ball 90 yards. It travels three-fourths of the distance to the hole. Write an equation you can use to find the distance d (in yards) from the tee to the hole.

Answer:

Given,

You hit a golf ball 90 yards. It travels three-fourths of the distance to the hole.

3/4 × D = 90

D = 360/3

D = 120

**GEOMETRY** Write an equation you can use to find the value of x.

Question 26.

Perimeter of triangle: 16 in.

Answer:

side of the triangle = x

Perimeter of triangle 16 in

P = a + b + c

16 in = x + x + x

3x = 16

x = 16/3

x = 5.3

Thus the side of the triangle is 5.3 inches.

Question 27.

Perimeter of square: 30 mm

Answer:

4x = 30

x = 30/4

x = 7.5 mm

Question 28.

**MODELING REAL LIFE**

You sell instruments at a Caribbean music festival. You earn $326 by selling 12 sets of maracas,6 sets of claves, and x djembe drums. Find the number of djembe drums you sold.

Answer:

Let the price of maracas be m

Let the price of claves be c

Let the price of djembe drums be x

Number of maracas = 12 sets

Number of claves = 6 sets

Number of djembe drums = xx

Total earned amount = $326

The equation would be

12m + 6c + dxx = 326

The cost for 1 maracas is $14

For 12 sets = 12 × 14 = $168

The cost for 1 clave = $5

For 6 sets = 6 × 5 = $30

The cost for 1 djembe drums is $16

For x sets = 16x

12m + 6c + dxx = 326

168 + 30 + 16x = 326

16x = 128

x = 128 ÷ 16

x = 8

Question 29.

**PROBLEM SOLVING**

Neil Armstrong set foot on the Moon 109.4 hours after Apollo 11departed from the Kennedy Space Center. Apollo 11landed on the Moon about 6.6 hours before Armstrong’s first step. How many hours did it take for Apollo 11 to reach the Moon?

Answer:

Given,

Neil Armstrong set foot on the Moon 109.4 hours after Apollo 11 departed from the Kennedy Space Center.

Apollo 11landed on the Moon about 6.6 hours before Armstrong’s first step.

To find how many hours did it take for Apollo 11 to reach the Moon we have to subtract 6.6 hours from 109.4 hours

109.4 – 6.6 = 102.8 hours

Thus it took 102.8 hours for Apollo 11 to reach the Moon.

Question 30.

**LOGIC**

You buy a basket of 24 strawberries. You eat them as you walk to the beach. It takes the same amount of time to walk each block. When you are halfway there, half of the berries are gone. After walking 3 more blocks, you still have 5 blocks to go. You reach the beach 28 minutes after you began. One-sixth of your strawberries are left.

a. Is there enough information to find the time it takes to walk each block? Explain.

Answer:

Yes, you are given enough information to find the time to walk each block

To find the total number of block you, add

3 + 5 + 8 = 16

Also the time it takes to walk the 16 blocks is given 28 minutes.

b. Is there enough information to find how many strawberries you ate while walking the last block? Explain.

Answer:

No, there is not enough information to find how many strawberries ate while walking the last block.

You are only given the amount of strawberries you started with 24 and what you have left (1/6) with 5 blocks to go. Therefore you can only be given how many strawberries were eaten walking the last block.

Question 31.

**DIG DEEPER!**

Find a sales receipt from a store that shows the total price of the items and the total amount paid including sales tax.

a. Write an equation you can use to find the sales tax rate r.

b. Can you use r to find the percent for the sales tax? Explain.

Answer:

Total amount paid = total price + (total price × sales tax rate)

sample equation

14.20 = 13.27 + (13.27 × 0.07)

Yes, you can use r to find the percent for the sales tax.

Multiplying r by 100 gives the percent for the sales tax.

Question 32.

**GEOMETRY**

A square is cut from a rectangle. The side length of the square is half of the unknown width w. The area of the shaded region is 84 square inches. Write an equation you can use to find the width (in inches).

Answer:

Given,

A square is cut from a rectangle. The side length of the square is half of the unknown width w.

The area of the shaded region is 84 square inches.

84 square inches divided by 14 inches equals 6

84 divided by 14 = s

84 ÷ 14 = s

### Lesson 6.2 Solving Equations Using Addition or Subtraction

**EXPLORATION 1**

Solving an Equation Using a Tape Diagram

Work with a partner. A student solves an equation using the tape diagrams below.

a. What equation did the student solve? What is the solution?

Answer: x + 4 = 12

Explanation:

By seeing step 1 we can say that the equation for the above tape diagram x + 4 = 12

b. Explain how the tape diagrams in Steps 2 and 3 relate to the equation and its solution.

Answer:

By seeing the steps 2 and 3 we can say

8 + 4 = 12

x + 4 = 12

x = 12 – 4

x = 8

**EXPLORATION 2**

Solving an Equation Using a Model

Work with a partner.

a. How are the two sides of an equation similar to a balanced scale?

b. When you add weight to one side of a balanced scale, what can you do to balance the scale? What if you subtract weight from one side of a balanced scale? How does this relate to solving an equation?

c. Use a model to solve x + 2 = 7. Describe how you can solve the equation algebraically.

Answer:

x + 2 = 7

x = 7 – 2

x = 5

**Try It**

**Tell whether the given value is a solution of the equation.**

Question 1.

a + 6 = 17; a = 9

Answer: not a solution

Explanation:

Given the equation a + 6 = 17

when a = 9

9 + 6 = 17

15 ≠ 17

Thus the equation is not a solution.

Question 2.

9 – g = 5; g = 3

Answer: not a solution

Explanation:

Given the equation 9 – g = 5

where g = 3

9 – 3 = 5

6 ≠ 5

Thus the equation is not a solution.

Question 3.

35 – 7n; n = 5

Answer: solution

Explanation:

Given the equation 35 – 7n

where n = 5

35 – 7(5)

35 – 35 = 0

Thus the equation is a solution.

Question 4.

\(\frac{q}{2}\) = 28; q = 14

Answer: not a solution

Explanation:

Given the equation \(\frac{q}{2}\) = 28

where q = 14

\(\frac{14}{2}\) = 28

7 ≠ 28

Thus the equation is not a solution.

You can use inverse operations to solve equations. Inverse operations “undo” each other. Addition and subtraction are inverse operations.

**Solve the equation. Check your solution.**

Question 5.

k – 3 = 1

Answer: k = 4

Explanation:

Given the equation k – 3 = 1

k = 1 + 3

k = 4

Question 6.

n – 10 = 4

Answer: n = 14

Explanation:

Given the equation n – 10 = 4

n = 4 + 10

n = 14

Question 7.

15 = r – 6

Answer: r = 21

Explanation:

Given the equation 15 = r – 6

15 + 6 = r

r = 21

Question 8.

s + 8 = 17

Answer: s = 9

Explanation:

Given the equation s + 8 = 17

s = 17 – 8

s = 9

Question 9.

9 = y + 6

Answer: y = 3

Explanation:

Given the equation 9 = y + 6

9 – 6 = y

y = 3

Question 10.

13 + m = 20

Answer: m = 7

Explanation:

Given the equation 13 + m = 20

m = 20 – 13

m = 7

**Self-Assessment for Concepts & Skills**

Solve each exercise. Then rate your understanding of the success criteria in your journal.

**CHECKING SOLUTIONS** Tell whether the given value is a solution of the equation.

Question 11.

n + 8 = 42; n = 36

Answer: not a solution

Explanation:

Given the equation n + 8 = 42

where n = 36

36 + 8 = 44

44 ≠ 42

Thus the value is not a solution.

Question 12.

g – 9 = 24; g = 35

Answer: not a solution

Explanation:

Given the equation g – 9 = 24

where g = 35

35 – 9 = 24

26 ≠ 24

Thus the value is not a solution.

**SOLVING EQUATIONS** Solve the equation. Check your solution.

Question 13.

x – 8 = 12

Answer: 20

Explanation:

Given the equation x – 8 = 12

x = 12 + 8

x = 20

Question 14.

b + 14 = 33

Answer: 19

Explanation:

Given the equation b + 14 = 33

b = 33 – 14

b = 19

Question 15.

**WRITING**

When solving x + 5 =16, why do you subtract 5 from the left side of the equation? Why do you subtract 5 from the right side of the equation?

Answer:

To solve the equation we have to subtract 5.

x + 5 = 16

x = 16 – 5

x = 11

Question 16.

**REASONING**

Do the equations have the same solution? Explain your reasoning.

x – 8 = 6

x – 6 = 8

Answer:

i. x – 8 = 6

x = 6 + 8

x = 14

ii. x – 6 = 8

x = 8 + 6

x = 14

Yes both the equations has same solutions.

Question 17.

**STRUCTURE**

Just by looking at the equation x + 6 + 2x = 2x + 6 + 4, find the value of x. Explain your reasoning.

Answer:

x + 6 + 2x = 2x + 6 + 4

3x + 6 = 2x + 10

3x – 2x = 10 – 6

x = 4

Question 18.

An emperor penguin is 45 inches tall. It is 24 inches taller than a rockhopper penguin. Write and solve an equation to find the height (in inches) of a rockhopper penguin. Is your answer reasonable? Explain.

Answer:

Given,

An emperor penguin is 45 inches tall. It is 24 inches taller than a rockhopper penguin.

45 inches – 24 inches = 21 inches

Thus the height of the rockhopper penguin is 21 inches.

Question 19.

**DIG DEEPER!**

You get in an elevator and go up 2 floors and down8 floors before exiting. Then you get back in the elevator and go up 4 floors before exiting on the 12th floor. On what floors did you enter the elevator?

Answer: The answer to your question is 14 floor

Explanation:

To solve this problem start from the end changing the sense if it says up, then consider the action as down, etc.

Last floor = 12

Go down 4 floors = 12 – 4 = 8

Go up 8 floors = 8 + 8 = 16

Go down 2 floors = 16 – 2 = 14

### Solving Equations Using Addition or Subtraction Homework & Practice 6.2

**Review & Refresh**

**Write the word sentence as an equation.**

Question 1.

Th sum of a number x and 9 is 15.

Answer: x + 9 = 15

Explanation:

We have to write the equation for the word sentence

The phrase sum indicates ‘+’

The equation would be x + 9 = 15

Question 2.

12 less than a number m equals 20.

Answer: 12 – m = 20

Explanation:

We have to write the equation for the word sentence

The phrase less than indicates ‘-‘

The equation would be 12 – m = 20

Question 3.

The product of a number d and 7 is 63.

Answer: d7 = 63

Explanation:

We have to write the equation for the word sentence

The phrase product indicates ‘×’

The equation would be d × 7 = 63

Question 4.

18 divided by a number s equals 3.

Answer: 18 ÷ s = 3

Explanation:

We have to write the equation for the word sentence

The phrase divided by indicates ‘÷’

The equation would be 18 ÷ s = 3

**Divide. Write the answer in simplest form.**

Question 5.

\(\frac{1}{2}\) ÷ \(\frac{1}{4}\)

Answer: 2

Explanation:

Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

\(\frac{1}{2}\) × \(\frac{4}{1}\) = 2

Question 6.

12 ÷ \(\frac{3}{8}\)

Answer: 32

Explanation:

Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

12 × \(\frac{8}{3}\)

= 4 × 8

= 32

Question 7.

8 ÷ \(\frac{4}{5}\)

Answer: 10

Explanation:

Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

8 × \(\frac{5}{4}\)

= 2 × 5

= 10

Question 8.

\(\frac{7}{9}\) ÷ \(\frac{3}{2}\)

Answer: \(\frac{14}{27}\)

Explanation:

Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

\(\frac{7}{9}\) × \(\frac{2}{3}\) = \(\frac{14}{27}\)

Question 9.

Which ratio is not equivalent to 72 : 18?

A. 36 : 9

B. 18 : 6

C. 4 : 1

D. 288 : 72

Answer: B. 18 : 6

Explanation:

72 : 18 = 36:9, 4 : 1, 288 : 72

18 : 6 is not equivalent to 72 : 18

Thus the correct answer is option B.

**Evaluate the expression.**

Question 10.

(2 + 5^{2}) ÷ 3

Answer: 9

Explanation:

Given the expression (2 + 5^{2}) ÷ 3

(2 + 25) ÷ 3

27 ÷ 3 = 9

Question 11.

6 + 2^{3} . 3 – 5

Answer: 25

Explanation:

Given the expression 6 + 2^{3} . 3 – 5

6 + 8 . 3 – 5

6 + 24 – 5

6 + 19

25

Question 12.

4 . [3 + 3(20 – 4^{2} – 2)]

Answer: 36

Explanation:

Given the expression 4 . [3 + 3(20 – 4^{2} – 2)]

4(3 + 3(20 – 16 – 2))

4(3 + 3(2))

4 (3 + 6)

4(9)

36

Question 13.

Find the missing values in the ratio table. Then write the equivalent ratios.

Answer:

**Concepts, Skills, & Problem Solving**

**CHOOSE TOOLS** Use a model to solve the equation. (See Explorations 1 and 2, p. 251.)

Question 14.

n + 7 = 9

Answer: n = 2

Explanation:

n + 7 = 9

n = 9 – 7

n = 2

Question 15.

t + 4 = 5

Answer: t = 1

Explanation:

t + 4 = 5

t = 5 – 4

t = 1

Question 16.

c + 2 = 8

Answer: c = 6

Explanation:

c + 2 = 8

c = 8 – 2

c = 6

**CHECKING SOLUTIONS** Tell whether the given value is a solution of the equation.

Question 17.

x + 42 = 85; x = 43

Answer: solution

Explanation:

x + 42 = 85

Substitute the value of x in the equation

x = 43

43 + 42 = 85

Question 18.

8b = 48; b = 6

Answer: solution

Explanation:

8b = 48

Substitute the value of b in the equation

b = 6

8(6) = 48

48 = 48

Question 19.

19 – g = 7; g = 15

Answer: not a solution

Explanation:

19 – g = 7

Substitute the value of g in the equation

g = 15

19 – 15 = 7

2 ≠ 7

This is not a solution

Question 20.

\(\frac{m}{4}\) = 16; m = 4

Answer: not a solution

Explanation:

\(\frac{m}{4}\) = 16

Substitute the value of m in the equation

\(\frac{4}{4}\) = 16

1 ≠ 16

This is not a solution

Question 21.

w + 23 = 41; w = 28

Answer: not a solution

Explanation:

w + 23 = 41

Substitute the value of w in the equation

28 + 23 = 41

51 ≠ 41

This is not a solution

Question 22.

s – 68 = 11; s = 79

Answer: solution

Explanation:

Given,

s – 68 = 11

Substitute the value of s in the equation

s = 79

79 – 68 = 11

11 = 11

This is a solution

**SOLVING EQUATIONS** Solve the equation. Check your solution.

Question 23.

y – 7 = 3

Answer:

Given the equation

y – 7 = 3

y = 3 + 7

y = 10

Question 24.

z – 3 = 13

Answer:

Given the equation

z – 3 = 13

z = 13 +3

z = 16

Question 25.

8 = r – 14

Answer:

Given the equation

8 = r – 14

r = 8 + 14

r = 22

Question 26.

p + 5 = 8

Answer:

Given the equation

p + 5 = 8

p = 8 – 5

p = 3

Question 27.

k + 6 = 18

Answer:

Given the equation

k + 6 = 18

k = 18 – 6

k = 12

Question 28.

64 = h + 30

Answer:

Given the equation

64 = h + 30

h = 64 – 30

h = 34

Question 29.

f – 27 = 19

Answer:

Given the equation

f – 27 = 19

f = 19 +27

f = 46

Question 30.

25 = q + 14

Answer:

Given the equation

25 = q + 14

q = 25 – 14

q = 11

Question 31.

\(\frac{3}{4}\) = j – \(\frac{1}{2}\)

Answer:

Given the equation

\(\frac{3}{4}\) = j – \(\frac{1}{2}\)

\(\frac{3}{4}\) + \(\frac{1}{2}\) = j

j = 1 \(\frac{1}{4}\)

Question 32.

x + \(\frac{2}{3}\) = \(\frac{9}{10}\)

Answer:

Given the equation

x + \(\frac{2}{3}\) = \(\frac{9}{10}\)

x = \(\frac{9}{10}\) – \(\frac{2}{3}\)

x = \(\frac{7}{30}\)

Question 33.

1.2 = m – 2.5

Answer:

Given the equation

1.2 = m – 2.5

m = 1.2 + 2.5

m = 3.7

Question 34.

a + 5.5 = 17.3

Answer:

Given the equation

a + 5.5 = 17.3

a = 17.3 – 5.5

a = 11.8

**YOU BE THE TEACHER** Your friend solves the equation. Is your friend correct? Explain your reasoning.

Question 35.

Answer:

x + 7 = 13

x = 13 – 7

x = 4

Your friend is incorrect

Question 36.

Answer:

34 = y – 12

y – 12 = 34

y = 34 + 12

y = 46

Question 37.

**MODELING REAL LIFE**

The main span of the Sunshine SkywayBridge is 366 meters long. The bridge’s main span is 30 meters shorter than the main span of the Dames Point Bridge. Write and solve an equation to find the length (in meters) of the main span of the Dames Point Bridge.

Answer:

Given,

The main span of the Sunshine SkywayBridge is 366 meters long.

The bridge’s main span is 30 meters shorter than the main span of the Dames Point Bridge.

336 – 30 = 306

Let the main span of the Sunshine SkywayBridge be x

Let the main span of the Dames Point Bridge be y

x – y = 306

Question 38.

**PROBLEM SOLVING**

A park has 22 elm trees. Elm leaf beetles have been attacking the trees. After removing several of the diseased trees, there are 13 healthy elm trees left. Write and solve an equation to find the number of elm trees that were removed.

Answer:

Given,

A park has 22 elm trees. Elm leaf beetles have been attacking the trees.

After removing several of the diseased trees, there are 13 healthy elm trees left.

x – y = 9

22 – 13 = 9

Thus the number of trees removed 9.

Question 39.

**PROBLEM SOLVING**

The area of Jamaica is 6460 square miles less than the area of Haiti. Find the area (in square miles) of Haiti.

Answer:

Given,

The area of Jamaica is 6460 square miles less than the area of Haiti.

Y = X – 6460

Y = Haiti

X = area of Jamaica

Question 40.

**REASONING**

The solution of the equation x+ 3 = 12 is shown. Explain each step. Use a property, if possible.

Answer:

The sum of a number x and 3 is 12

x + 3 = 12

x = 12 – 3

x = 9

**WRITING EQUATIONS** Write the word sentence as an equation. Then solve the equation.

Question 41.

13 subtracted from a number w is 15.

Answer: w – 13 = 15

Explanation:

We have to write the equation for the word sentence

The phrase subtracted indicates ‘-‘

The equation would be w – 13 = 15

Question 42.

A number k increased by 7 is 34.

Answer: K + 7 = 34

Explanation:

We have to write the equation for the word sentence

The phrase increased indicates ‘+’

The equation would be K + 7 = 34

Question 43.

9 is the difference of a number n and 7.

Answer: n – 7 = 9

Explanation:

We have to write the equation for the word sentence

The phrase difference indicates ‘-‘

The equation would be n – 7 = 9

Question 44.

93 is the sum of a number g and 58.

Answer: g + 58 = 93

Explanation:

We have to write the equation for the word sentence

The phrase sum indicates ‘+’

The equation would be g + 58 = 93

Question 45.

11 more than a number k equals 29.

Answer: 11 + k = 29

Explanation:

We have to write the equation for the word sentence

The phrase more than indicates ‘+’

The equation would be 11 + k = 29

Question 46.

A number p decreased by 19 is 6.

Answer: p – 19 = 6

Explanation:

We have to write the equation for the word sentence

The phrase decreased indicates ‘-‘

The equation would be p – 19 = 6

Question 47.

46 is the total of 18 and a number d.

Answer: 18 + d = 46

Explanation:

We have to write the equation for the word sentence

The phrase total indicates ‘+’

The equation would be 18 + d = 46

Question 48.

84 is 99 fewer than a number c.

Answer: 84 = 99 – c

Explanation:

We have to write the equation for the word sentence

The phrase fewer than indicates ‘-‘

The equation would be 84 = 99 – c

**SOLVING EQUATIONS** Solve the equation. Check your solution.

Question 49.

b + 7 + 12 = 30

Answer:

Given the equation

b + 7 + 12 = 30

b = 30 – 19

b = 11

Question 50.

y + 4 − 1 = 18

Answer:

Given the equation

y + 4 − 1 = 18

y + 3 = 18

y = 18 – 3

y = 15

Question 51.

m + 18 + 23 = 71

Answer:

Given the equation

m + 18 + 23 = 71

m + 41 = 71

m = 71 – 41

m = 30

Question 52.

v − 7 = 9 + 12

Answer:

Given the equation

v − 7 = 9 + 12

v – 7 = 21

v = 21 + 7

v = 28

Question 53.

5 + 44 = 2 + r

Answer:

Given the equation

5 + 44 = 2 + r

49 = 2 + r

r = 49 – 2

r = 47

Question 54.

22 + 15 = d− 17

Answer:

Given the equation

22 + 15 = d− 17

37 = d – 17

d = 37 + 17

d = 54

**GEOMETRY** Solve for x.

Question 55.

Perimeter = 48 ft

Answer:

P = a + b + c

48 ft = x + 20 + 12

x = 48 – 32

x = 16 ft

Question 56.

Perimeter = 132 in.

Answer:

P = a + b + c + d

132 = 34 + 16 + 34 + x

132 – 84 = x

x = 50 in

Question 57.

Perimeter = 93 ft

Answer:

P = 8(a + b + c + d + e)

93 ft = 8(18 + 18 + 15 + d + 15)

d = 93/528

d = 0.17

Question 58.

**SIMPLIFYING AND SOLVING** Compare and contrast the two problems.

Answer:

2(x + 3) – 4

= 2x + 6 – 4

= 2x + 2

Question 59.

**PUZZLE**

In a magic square, the sum of the numbers in each row, column, and diagonal is the same. Find the values of a, b, and c. Justify your answers.

Answer:

The sum of rows and columns is 53.

a = 22

b = 0

c = 0

Question 60.

**REASONING**

On Saturday, you spend $33, give $15 to a friend, and receive $20 for mowing your neighbor’s lawn. You have $21 left. Use two methods to find how much money you started with that day.

Answer:

Given,

On Saturday, you spend $33, give $15 to a friend, and receive $20 for mowing your neighbor’s lawn.

You have $21 left.

x = a + b + c – d

x = 33 + 15 + 20 – 21

x = 68 – 21

x = 47

Question 61.

**DIG DEEPER!**

You have $15.

a. How much money do you have left if you ride each ride once?

b. Do you have enough money to ride each ride twice? Explain.

Answer:

a. bumper cost : $1.75

super pendulum : $1.25 + $1.50= $2.75

giant slide : $1.75-$0.50= $1.25

ferris wheels : $1.50+$0.50=$2

total money spent=$7.75

money left=$7.75-$15=$7.25

b. No,

money required to ride once =$7.75

total money required to ride twice=$7.75+$7.75=$15.5

Question 62.

**CRITICAL THINKING**

Consider the equation 15 − y = 8. Explain how you can solve the equation using the Addition and Subtraction Properties of Equality.

Answer:

15 − y = 8

15 = 8 + y

8 + y = 15

y = 15 – 8

y = 7

### Lesson 6.3 Solving Equations Using Multiplication or Division

**EXPLORATION 1**

Solving an Equation Using a Tape Diagram

Work with a partner. A student solves an equation using the tape diagrams below.

a. What equation did the student solve? What is the solution?

Answer:

ax = b

4x = 20

x = 20/4

x = 5

b. Explain how the tape diagrams in Steps 2 and 3 relate to the equation and its solution.

Answer:

Step 2 and step 3 shows that x = 5

**EXPLORATION 2**

Solving an Equation Using a Model

Work with a partner. Three robots go out to lunch. They decide to split the $12 bill evenly. The scale represents the number of robots and the price of the meal.

a. How much does each robot pay?

Answer:

Three robots go out to lunch.

They decide to split the $12 bill evenly.

12/3 = 4

Thus each robot pay $4.

b. When you triple the weight on one side of a balanced scale, what can you do to balance the scale? What if you divide the weight on one side of a balanced scale in half? How does this relate to solving an equation?

c. Use a model to solve 5x = 15. Describe how you can solve the equation algebraically.

Answer:

5x = 15

x = 15/5

x = 3

**Try It**

**Solve the equation. Check your solution.**

Question 1.

\(\frac{a}{8}\) = 6

Answer: a = 48

Explanation:

Given the equation

\(\frac{a}{8}\) = 6

a = 6 × 8

a = 48

Question 2.

14 = \(\frac{2y}{5}\)

Answer: y = 35

Explanation:

Given the equation

14 = \(\frac{2y}{5}\)

14 × 5 = 2y

2y = 70

y = 70/2

y = 35

Question 3.

3z ÷ 2 = 9

Answer: z = 6

Explanation:

Given the equation

3z ÷ 2 = 9

3z = 9 × 2

3z = 18

z = 18/3

z = 6

Question 4.

p . 3 = 18

Answer: p = 6

Explanation:

Given the equation

p . 3 = 18

p = 18/3

p = 6

Question 5.

12q = 60

Answer: q = 5

Explanation:

Given the equation

12q = 60

q = 60/12

q = 5

Question 6.

81 = 9r

Answer: r = 9

Explanation:

Given the equation

81 = 9r

r = 81/9

r = 9

**Self-Assessment for Concepts & Skills**

Solve each exercise. Then rate your understanding of the success criteria in your journal.

**SOLVING EQUATIONS** Solve the equation. Check your solution.

Question 7.

6 = \(\frac{2y}{3}\)

Answer: y = 9

Explanation:

Given the equation

6 = \(\frac{2y}{3}\)

6 × 3 = 2y

2y = 18

y = 18/2

y = 9

Question 8.

8s = 56

Answer: s = 7

Explanation:

Given the equation

8s = 56

s = 56/8

s = 7

Question 9.

**WHICH ONE DOESN’T BELONG?**

Which equation does not belong with the other three? Explain your reasoning.

Answer: \(\frac{1}{4}\)x = 27 does not belong with the other three.

Because

3x= 36

x = 36/3

x = 12

3/4 x = 9

3x = 36

x = 36/3

x = 12

4x = 48

x = 48/4

x = 12

**STRUCTURE** Just by looking at the equation, find the value of x. Explain your reasoning.

Question 10.

5x + 3x = 5x + 18

Answer:

Given the equation

x(5+3)=5x+18

8x=5x+18

8x-5x=18

3x=18

x=18/3

x=6

Question 11.

8x + \(\frac{x}{2}\) = 8x + 6

Answer:

Given the equation

8x + \(\frac{x}{2}\) = 8x + 6

x (8 + \(\frac{1}{2}\) ) = 8x + 6

8.5x = 8x + 6

8.5x – 8x = 6

0.5x = 6

x = 6/0.5

x = 12

Question 12.

The area of the screen of the smart watch is shown. What are possible dimensions for the length and the width of the screen? Justify your answer.

Answer:

Given,

Area = 1625 sq.mm

L = 65 mm

W = 25 mm

We know that,

Area of the rectangle = l × w

1625 = 65 × 25

Thus the length and width of the smart watch is 65 mm and 25 mm.

Question 13.

A rock climber climbs at a rate of 720 feet per hour. Write and solve an equation to find the number of minutes it takes for the rock climber to climb 288 feet.

Answer:

Given,

A rock climber climbs at a rate of 720 feet per hour.

The equation is y = 12x

It takes 24 minutes for the rock climber to get 288 feet

288 = 12x

288/12 = 12x/12

24 = x

Now we have time in minutes that it takes to get 288 feet.

Question 14.

**DIG DEEPER!**

A gift card stores data using a black, magnetic stripe on the back of the card. Find the width w of the stripe.

Answer:

Given,

Area = 46 \(\frac{3}{4}\) sq. cm

L = 8 \(\frac{1}{2}\) cm

w = 4 cm + x+ \(\frac{2}{3}\) cm

We know that,

Area of the rectangle = l × w

46 \(\frac{3}{4}\) = 4 cm + x+ \(\frac{2}{3}\) × 8 \(\frac{1}{2}\)

= (4 + 0.6 + x) × 8.5

46.75 = 34 + 5.4 + 8.5x

8.5x = 46.75 – 34 – 5.1

8.5x = 7.6

x = 7.6/8.5

x = 0.89

Thus the width is 0.89 cm

### Solving Equations Using Multiplication or Division Homework & Practice 6.3

**Review & Refresh**

**Solve the equation. Check your solution.**

Question 1.

y – 5 = 6

Answer: y = 11

Explanation:

Given the equation

y – 5 = 6

y = 6 + 5

y = 11

Question 2.

m + 7 = 8

Answer: 1

Explanation:

Given the equation

m + 7 = 8

m = 8 – 7

m = 1

Question 3.

\(\frac{7}{8}\) = \(\frac{1}{4}\) + 9

Answer:

\(\frac{1}{4}\) + 9 = \(\frac{9}{4}\)

\(\frac{7}{8}\) ≠ \(\frac{9}{4}\)

not a solution

Question 4.

What is the value of a^{3} when a= 4?

A. 12

B. 43

C. 64

D. 81

Answer: 64

Explanation:

a^{3} when a= 4

4 × 4 × 4 = 64

Thus the correct answer is option C.

**Multiply. Write the answer in simplest form.**

Question 5.

\(\frac{1}{5}\) . \(\frac{2}{9}\)

Answer:

For fraction multiplication, multiply the numerators and then multiply the denominators to get

\(\frac{1}{5}\) . \(\frac{2}{9}\) = \(\frac{2}{45}\)

Question 6.

\(\frac{5}{12}\) × \(\frac{4}{7}\)

Answer:

For fraction multiplication, multiply the numerators and then multiply the denominators to get

\(\frac{5}{12}\) × \(\frac{4}{7}\) = \(\frac{5}{21}\)

Question 7.

2\(\frac{1}{3}\) . \(\frac{3}{10}\)

Answer:

For fraction multiplication, multiply the numerators and then multiply the denominators to get

2\(\frac{1}{3}\) = \(\frac{7}{3}\)

\(\frac{7}{3}\) × \(\frac{3}{10}\) = \(\frac{21}{30}\)

Question 8.

1\(\frac{3}{4}\) × 2\(\frac{2}{3}\)

Answer:

1\(\frac{3}{4}\) = \(\frac{7}{4}\)

2\(\frac{2}{3}\) = \(\frac{8}{4}\)

\(\frac{7}{4}\) × \(\frac{8}{4}\) = \(\frac{56}{16}\)

**Multiply.**

Question 9.

Answer: 0.36

Explanation:

Multiply the two decimals

0.4 × 0.9 = 0.36

Question 10.

Answer: 0.39

Explanation:

Multiply the two decimals

0.78 × 0.5 = 0.39

Question 11.

2.63 × 4.31

Answer: 11.3353

Explanation:

Multiply the two decimals

2.63 × 4.31 = 11.3353

Question 12.

1.115 × 3.28

Answer: 69.2

Explanation:

Multiply the two decimals

1.115 × 3.28 = 69.2

**Concepts, Skills, &Problem Solving**

**CHOOSE TOOLS** Use a model to solve the equation. (See Explorations 1 and 2, p. 259.)

Question 13.

8x = 8

Answer: 1

Explanation:

Given the equation

8x = 8

x = 8/8

x = 1

Question 14.

9 = 3y

Answer: 3

Explanation:

Given the equation

9 = 3y

y = 9/3

y = 3

Question 15.

2z = 14

Answer: 7

Explanation:

Given the equation

2z = 14

z = 14/2

z = 7

**SOLVING EQUATIONS** Solve the equation. Check your solution.

Question 16.

\(\frac{s}{10}\) = 7

Answer: 70

Explanation:

Given the equation

\(\frac{s}{10}\) = 7

s = 7 × 10

s = 70

Question 17.

6 = \(\frac{t}{s}\)

Answer: 6s = t

Explanation:

Given the equation

6 = \(\frac{t}{s}\)

t = 6s

Question 18.

5x ÷ 6 = 20

Answer:

Given the equation

5x ÷ 6 = 20

5x = 20 × 6

5x = 120

x = 120/5

x = 24

Question 19.

24 = \(\frac{3}{4}\)r

Answer:

Given the equation

24 = \(\frac{3}{4}\)r

24 × 4 = 3r

96 = 3r

r = 32

Question 20.

3a = 12

Answer: 4

Explanation:

Given the equation

3a = 12

a = 12/3

a = 4

Question 21.

5 . z = 35

Answer: 7

Explanation:

Given the equation

5 . z = 35

z = 35/5

z = 7

Question 22.

40 = 4y

Answer: 10

Explanation:

Given the equation

40 = 4y

40/4 = y

y = 10

Question 23.

42 = 7k

Answer: 6

Explanation:

Given the equation

42 = 7k

7k = 42

k = 42/7

Question 24.

7x = 105

Answer: 15

Explanation:

Given the equation

7x = 105

x = 105/7

x = 15

Question 25.

75 = 6 . w

Answer: 12.5

Explanation:

Given the equation

75 = 6 . w

w = 75/6

w = 12.5

Question 26.

13 = d ÷ 6

Answer: 78

Explanation:

Given the equation

13 = d ÷ 6

d = 13 × 6

d = 78

Question 27.

9 = v ÷ 5

Answer: 45

Explanation:

Given the equation

9 = v ÷ 5

v = 9 × 5

v = 45

Question 28.

\(\frac{5d}{9}\) = 10

Answer: 18

Explanation:

Given the equation

\(\frac{5d}{9}\) = 10

5d = 10 × 9

5d = 90

d = 18

Question 29.

\(\frac{3}{5}\) = 4m

Answer: 0.15

Explanation:

Given the equation

\(\frac{3}{5}\) = 4m

3 = 4m × 5

20m = 3

m = 3/20

m = 0.15

Question 30.

136 = 17b

Answer: 19.4

Explanation:

Given the equation

136 = 17b

b = 136/17

b = 19.4

Question 31.

\(\frac{2}{3}\) = \(\frac{1}{4}\)k

Answer: 2.6

Explanation:

Given the equation

\(\frac{2}{3}\) = \(\frac{1}{4}\)k

k = \(\frac{8}{3}\)

k = 2.6

Question 32.

\(\frac{2c}{15}\) = 8.8

Answer: 66

Explanation:

Given the equation

\(\frac{2c}{15}\) = 8.8

2c = 8.8 × 15

2c = 132

c = 132/2

c = 66

Question 33.

7b ÷ 12 = 4.2

Answer: 7.2

Explanation:

Given the equation

7b ÷ 12 = 4.2

7b = 4.2 × 12

b = 7.2

Question 34.

12.5 . n = 32

Answer: 2.56

Explanation:

Given the equation

12.5 . n = 32

n = 32/12.5

n = 2.56

Question 35.

3.4 m = 20.4

Answer: m = 6

Explanation:

Given the equation

3.4 m = 20.4

m = 20.4/3.4

m = 6

Question 36.

**YOU BE THE TEACHER**

Your friend solves the equation x ÷ 4 =28. Is your friend correct? Explain your reasoning.

Answer: Your friend is correct

Explanation:

Your friend solves the equation x ÷ 4 =28.

x ÷ 4 = 28

x = 28/4

x = 7

Question 37.

**ANOTHER WAY**

Show how you can solve the equation 3x = 9 by multiplying each side by the reciprocal of 3.

Answer:

3x = 9

x = 9 × 1/3

x = 3

Question 38.

**MODELING REAL LIFE**

Forty-five basketball players participate in a three-on-three tournament. Write and solve an equation to find the number of three-person teams in the tournament.

Answer: 15

Explanation:

Let the number of teams be x

x × 3 = 45

x = 45/3

x = 15

Question 39.

**MODELING REAL LIFE**

A theater has 1200 seats. Each row has 20 seats. Write and solve an equation to find the number of rows in the theater.

Answer:

Given,

A theater has 1200 seats. Each row has 20 seats.

Let x be the number of rows.

1200 = 20 × x

x = 1200/20

x = 60

**GEOMETRY** Solve for x. Check your answer.

Question 40.

Area = 45 square units

Answer:

l = x

w = 5

Area = 45 square units

We know that,

Area of the Rectangle = l × w

45 = x × 5

x = 45/5

x = 9 units

Question 41.

Area = 176 square units

Answer:

a = 16

Area = 176 square units

We know that,

Area of the square = a × a

176 = 16 × x

x = 16

Question 42.

**LOGIC**

Ona test, you earn 92% of the possible points by correctly answering 6 five-point questions and 8 two-point questions. How many points p is the test worth?

Answer:

Given,

Ona test, you earn 92% of the possible points by correctly answering 6 five-point questions and 8 two-point questions.

(6 × 5) + (8 × 2) = 46

92 × 1/100 = 46

0.92x = 46

x = 46/0.92

x = 50

Question 43.

**MODELING REAL LIFE**

You use index cards to play a homemade game. The object is to be the first to get rid of all your cards. How many cards are in your friend’s stack?

Answer:

The number of cards in your friend’s stack divided by the height of your’s friends stack equals the number of cards in your stack divided by the height of your stack.

x = the number of cards in your friend’s stack

x ÷ 5 = 48 ÷ 12

x ÷ 5 = 4

x = 4 × 5

x = 20

Question 44.

**DIG DEEPER!**

A slush drink machine fills 1440 cups in 24 hours.

a. Find the number c of cups each symbol represents.

b. To lower costs, you replace the cups with paper cones that hold 20% less. Find the number n of paper cones that the machine can fill in 24 hours.

Answer:

The number of symbols times the number of cups per symbol equals the total number of cups filled.

C = The number of cups filled

30 × c = 1440

c = 1440/30

c = 48

Question 45.

**NUMBER SENSE**

The area of the picture is 100 square inches. The length is 4 times the width. Find the length and width of the picture.

Answer:

Given,

The area of the picture is 100 square inches.

The length is 4 times the width.

We know that,

Area of Rectangle = l × w

100 sq. in = 4w × w

100 = 4w²

w = √25 = 5

L = 4w

L = 4 × 5

L = 20

### Lesson 6.4 Writing Equations in Two Variables

**EXPLORATION 1**

Writing Equations in Two Variables

Work with a partner. section 3.4 Exploration 1, you used a ratio table to create a graph for an airplane traveling 300 miles per hour. Below is one possible ratio table and graph.

a. Describe the relationship between the two quantities. Which quantity depends on the other quantity?

Answer: By seeing the above graph we can say that miles depend on hours (time).

b. Use variables to write an equation that represents the relationship between the time and the distance. What can you do with this equation? Provide an example.

c. Suppose the airplane is 1500 miles away from its destination. Write an equation that represents the relationship between time and distance from the destination. How can you represent this relationship using a graph?

Answer: The relationship between distance and time is distance is inversely proportional to the time.

5x = 1500

An equation in two variables represents two quantities that change in relationship to one another. A solution of an equation in two variables is an ordered pair that makes the equation true.

**Try It**

**Tell whether the ordered pair is a solution of the equation.**

Question 1.

y = 7x, (2, 21)

Answer: No

Explanation:

Given the equation y = 7x

y = 7 × 2

y = 14

21 ≠ 14

The ordered pair is not the solution.

Question 2.

y = 5x + 1; (3, 16)

Answer: Yes

Explanation:

Given the equation y = 5x + 1

y = 5 × 3 + 1

y = 15 + 1

y = 16

The ordered pair is the solution.

Question 3.

The equation y = 10x + 25 represents the amount y(in dollars) in your savings account after x weeks. Identify the independent and dependent variables. How much is in your savings account after 8 weeks?

Answer:

Because the amount y remaining depends on the number x weeks.

Y is the dependent variable

X is the independent variable

y = 10x + 25

After 8 weeks x = 8

y = 10 (8) + 25

y = 80 + 25

y = 105

**Graph the equation.**

Question 4.

y = 3x

Answer:

When x = 0

y = 3(0) = 0

A(x,y) = (0,0)

When x = 1

y = 3(1) = 3

B(x,y) = (3, 1)

When x = 2

y = 3(2) = 6

C(x,y) = (6, 2)

When x = 3

y = 3(3) = 9

D(x,y) = (9, 3)

Question 5.

y = 4x + 1

Answer:

y = 4x + 1

When x = 0

y = 4(0) + 1

y = 1

When x = 1

y = 4(1) + 1

y = 5

When x = 2

y = 4(2) + 1

y = 9

Question 6.

y = \(\frac{1}{2}\)x + 2

Answer:

Given,

y = \(\frac{1}{2}\)x + 2

when x = 0

y = \(\frac{1}{2}\)0 + 2

y = 2

when x = 1

y = \(\frac{1}{2}\)1 + 2

y = 2\(\frac{1}{2}\)

y = 2.5

when x = 2

y = \(\frac{1}{2}\)2 + 2

y = 1 + 2

y = 3

Question 7.

It costs $25 to rent a kayak plus $8 for each hour. Write and graph an equation that represents the total cost (in dollars) of renting the kayak.

Answer:

Given,

It costs $25 to rent a kayak plus $8 for each hour.

y = 8x + 25

**Self-Assessment for Concepts & Skills**

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 8.

**WRITING**

Describe the difference between independent variables and dependent variables.

Answer:

The independent variable is the cause. Its value is independent of other variables in your study. The dependent variable is the effect. Its value depends on changes in the independent variable.

**IDENTIFYING SOLUTIONS** Tell whether the ordered pair is a solution of the equation.

Question 9.

y = 3x + 8; (4, 20)

Answer:

Given the equation

y = 3x + 8

x = 4

y = 20

20 = 3(4) 8

20 = 12 + 8

20 = 20

The above equation is the solution.

Question 10.

y = 6x – 14; (7, 29)

Answer:

Given the equation

y = 6x – 14

29 = 6(7) – 14

29 = 42 – 14

29 ≠ 28

The above equation is not the solution.

Question 11.

**PRECISION**

Explain how to graph an equation in two variables.

Answer:

- Find three points whose coordinates are solutions to the equation. Organize them in a table.
- Plot the points in a rectangular coordinate system. Check that the points line up. …
- Draw the line through the three points. Extend the line to fill the grid and put arrows on both ends of the line.

Question 12.

**WHICH ONE DOESN’T BELONG?**

Which one does not belong with the other three? Explain your reasoning.

Answer: n = 4n – 6 does not belong to the other three equations because we can take n has common and we can solve the equation.

Remaining there is not possible to solve the equation.

Question 13.

A sky lantern rises at an average speed of 8 feet per second. Write and graph an equation that represents the relationship between the time and the distance risen. How long does it take the lantern to rise 100 feet?

Answer:

Given,

A sky lantern rises at an average speed of 8 feet per second.

the lantern to rise 100 feet = ?

8 feets = 1 sec

100 feets = 8 × x

x = 100/8

x = 12.5 sec

Question 14.

You and a friend start biking in opposite directions from the same point. You travel 108 feet every 8 seconds. Your friend travels 63 feet every 6 seconds. How far apart are you and your friend after 15 minutes?

Answer:

Given,

You and a friend start biking in opposite directions from the same point.

You travel 108 feet every 8 seconds. Your friend travels 63 feet every 6 seconds.

Your distance Y,

Y = 108ft/8 seconds × 60 sec/min × 15 min × 1mile/5280 ft

H is determined similarly

Total distance apart in miles = Y + H

You have only 36 minutes while he travels for all 40.

### Writing Equations in Two Variables Homework & Practice 6.4

**Review & Refresh**

**Solve the equation.**

Question 1.

4x = 36

Answer: 9

Explanation:

Given the equation 4x = 36

x = 36/4

x = 9

Question 2.

\(\frac{x}{8}\) = 5

Answer: 40

Explanation:

Given the equation \(\frac{x}{8}\) = 5

x = 5 × 8

x = 40

Question 3.

\(\frac{4x}{3}\) = 8

Answer: 6

Explanation:

Given the equation \(\frac{4x}{3}\) = 8

4x = 8 × 3

4x = 24

x = 24/4

x = 6

Question 4.

\(\frac{2}{5}\)x = 6

Answer: 15

Explanation:

Given the equation \(\frac{2}{5}\)x = 6

2x = 5 × 6

2x = 30

x = 30/2

x = 15

**Divide. Write the answer in simplest form.**

Question 5.

3\(\frac{1}{2}\) ÷ \(\frac{4}{5}\)

Answer: 4 \(\frac{3}{8}\)

Explanation:

Convert any mixed numbers to fractions.

Then your initial equation becomes:

3\(\frac{1}{2}\) = \(\frac{7}{2}\)

\(\frac{7}{2}\) × \(\frac{5}{4}\)

= \(\frac{35}{8}\)

Now convert the improper fraction to the mixed fraction.

\(\frac{35}{8}\) = 4 \(\frac{3}{8}\)

Question 6.

7 ÷ 5\(\frac{1}{4}\)

Answer: 1 \(\frac{1}{3}\)

Explanation:

Convert any mixed numbers to fractions.

Then your initial equation becomes:

7 ÷ 5\(\frac{1}{4}\)

5\(\frac{1}{4}\) = \(\frac{21}{4}\)

\(\frac{7}{1}\) ÷ \(\frac{21}{4}\) = 1 \(\frac{1}{3}\)

Question 7.

\(\frac{3}{11}\) ÷ 1\(\frac{1}{8}\)

Answer: \(\frac{8}{33}\)

Explanation:

Convert any mixed numbers to fractions.

Then your initial equation becomes:

\(\frac{3}{11}\) ÷ 1\(\frac{1}{8}\)

1\(\frac{1}{8}\) = \(\frac{9}{8}\)

\(\frac{3}{11}\) ÷ \(\frac{9}{8}\) = \(\frac{8}{33}\)

Question 8.

7\(\frac{1}{2}\) ÷ 1\(\frac{1}{3}\)

Answer: 5 \(\frac{5}{8}\)

Explanation:

Convert any mixed numbers to fractions.

Then your initial equation becomes:

7\(\frac{1}{2}\) = \(\frac{15}{2}\)

1\(\frac{1}{3}\) = \(\frac{4}{3}\)

\(\frac{15}{2}\) ÷ \(\frac{4}{3}\) = \(\frac{45}{8}\)

Now convert the improper fraction to the mixed fraction.

\(\frac{45}{8}\) = 5 \(\frac{5}{8}\)

Question 9.

Find the area of the carpet tile. Then find the area covered by120 carpet tiles.

Answer:

a = 16 in

Area of the square = a × a

A = 16 in × 16 in

A = 256 sq. in

Now we have to find the area covered by120 carpet tiles.

120 × 256 = 30720

**Copy and complete the statement. Round to the nearest hundredth if necessary.**

Question 10.

Answer: 800

Explanation:

convert from meters to centimeters

1 m = 100 cm

8 m = 8 × 100 cm = 800 cm

Thus 8m = 800cm

Question 11.

Answer:

Explanation:

Convert from ounces to pounds

88 oz = 5.5 pounds

Question 12.

Answer: 709 mL

Explanation:

Convert from cups to milliliters

1 cup = 236.588 mL

3 cups = 709 mL

Question 13.

Answer: 9.321 mi

Explanation:

Convert from km to miles

1 km = 0.621 mi

15 km = 15 × 0.621 mi

15 km = 9.321 miles

**Divide.**

Question 14.

\(\sqrt [ 6 ]{ 34.8 } \)

Answer: 6th root of 34.8 is 1.806

Question 15.

\(\sqrt [ 4 ]{ 12.8 } \)

Answer: 4th root of 12.8 is 1.891

Question 16.

45.92 ÷ 2.8

Answer: 16.2

Explanation:

Multiplying two decimal numbers

45.92 ÷ 2.8 = 16.2

Question 17.

39.525 ÷ 4.25

Answer: 9.3

Explanation:

Multiplying two decimal numbers

39.525 ÷ 4.25 = 9.3

**Concepts, Skills, &Problem Solving**

**WRITING EQUATIONS** Use variables to write an equation that represents the relationship between the time and the distance. (See Exploration 1, p. 265.)

Question 18.

An eagle flies 40 miles per hour.

Answer:

y = distance, x = time, rate = 40 miles per minute

distance = rate . time

y = 40 . x

Question 19.

A person runs 175 yards per minute.

Answer:

y = distance, x = time, rate = 175 yards per minute

distance = rate . time

so y = 175 . x

**IDENTIFYING SOLUTIONS** Tell whether the ordered pair is a solution of the equation.

Question 20.

y = 4x; (0, 4)

Answer:

x = 0

y = 4

4 = 4(0)

4 ≠ 0

The ordered pair is not a solution of the equation.

Question 21.

y = 3x; (2, 6)

Answer:

x = 2

y = 6

y = 3x

6 = 3(2)

6 = 6

The ordered pair is a solution of the equation.

Question 22.

y = 5x – 10; (3, 5)

Answer:

x = 3

y = 5

y = 5x – 10

5 = 5(3) – 10

5 = 15 – 10

5 = 5

The ordered pair is a solution of the equation.

Question 23.

y = x + 7; (1, 6)

Answer:

x = 1

y = 6

y = x + 7

6 = 1 + 7

6 ≠ 8

The ordered pair is not a solution of the equation.

Question 24.

y = x + 4; (2, 4)

Answer:

x = 2

y = 4

4 = 2 + 4

4 ≠ 6

The ordered pair is not a solution of the equation.

Question 25.

y = x – 5; (6, 11)

Answer:

x = 6

y = 11

11 = 6 – 5

11 ≠ 1

The ordered pair is not a solution of the equation.

Question 26.

y = 6x + 1; (2, 13)

Answer:

x = 2

y = 13

13 = 6(2) + 1

13 = 12 + 1

13 = 13

The ordered pair is a solution of the equation.

Question 27.

y = 7x + 2; (2, 0)

Answer:

x = 2

y = 0

0 = 7(2) + 2

0 = 14 + 2

0 ≠ 16

The ordered pair is not a solution of the equation.

Question 28.

y = 2x – 3; (4, 5)

Answer:

x = 4

y = 5

y = 2x – 3

5 = 2(4) – 3

5 = 8 – 3

5 = 5

The ordered pair is a solution of the equation.

Question 29.

y = 3x – 3; (1, 0)

Answer:

x = 1

y = 0

y = 3x – 3

0 = 3(1) – 3

0 = 3 – 3

0 = 0

The ordered pair is a solution of the equation.

Question 30.

7 = y – 5x; (4, 28)

Answer:

x = 4

y = 28

7 = y – 5x

7 = 28 – 5(4)

7 = 28 – 20

7 ≠ 8

The ordered pair is not a solution of the equation.

Question 31.

y + 3 = 6x; (3, 15)

Answer:

x = 3

y = 15

y + 3 = 6x

15 + 3 = 6(3)

18 = 18

The ordered pair is a solution of the equation.

Question 32.

**YOU BE THE TEACHER**

Your friend determines whether (5, 1) is a solution of y = 3x + 2. Is your friend correct? Explain your reasoning.

Answer:

x = 5

y = 1

y = 3x + 2

1 = 3(5) + 2

1 = 15 + 2

1 ≠ 17

Your friend is correct.

**IDENTIFYING VARIABLES** Identify the independent and dependent variables.

Question 33.

The equation A = 25w represents the area A (in square feet) of a rectangular dance floor with a width of w feet.

Answer:

The area of the dance floor (A) depends on the dance floor

A is the dependent variable

and w is the independent variable

Question 34.

The equation c= 0.09s represents the amount c(in dollars) of commission a salesperson receives for making a sale of s dollars.

Answer:

The commissioner a salesperson receives (c) depends on the sales the salesperson makes

c is dependent variable

s is independent variable

Question 35.

The equation t = 12p+ 12 represents the total cost t (in dollars) of a meal with a tip of p percent (in decimal form).

Answer:

The total cost of a meal depends on the tip of percent

the dependent variable is t

the independent variable is p

Question 36.

The equation h = 60 − 4m represents the height h(in inches) of the water in a tank m minutes after it starts to drain.

Answer:

The height of the water (h) depends on the minutes the tank has been draining

the dependent variable is h

the independent variable is m

**OPEN-ENDED** Complete the table by describing possible independent or dependent variables.

Answer:

37. Independent variable:

The grade you receive on the test dependent variable

38. Independent variable:

The time you reach your destination dependent variable.

39. Dependent variable:

The amount of minutes used to talk independent variable.

40. Dependent variable:

The number of hours you work independent variable.

**GRAPHING EQUATIONS** Graph the equation.

Question 41.

y = 2x

Answer:

Given,

y = 2x

when x = 0

y = 2(0)

y = 0

when x = 1

y = 2(1)

y = 2

when x = 2

y = 2(2)

y = 4

Question 42.

y = 5x

Answer:

Given,

y = 5x

when x = 0

y = 5(0)

y = 0

when x = 1

y = 5(1)

y = 5

Question 43.

y = 6x

Answer:

Question 44.

y = x + 2

Answer:

Given

y = x + 2

when x = 0

y = 0 + 2

y = 2

(x, y) = (0,2)

when x = 1

y = 1 + 2

y = 3

(x, y) = (1,3)

when x = 2

y = 2 + 2

y = 4

(x, y) = (2,4)

Question 45.

y = x + 0.5

Answer:

Given,

y = x + 0.5

when x = 0

y = 0 + 0.5

y = 0.5

when x = 1

y = 1 + 0.5

y = 1.5

Question 46.

y = x + 4

Answer:

Question 47.

y = x + 10

Answer:

Question 48.

y = 3x + 2

Answer:

Given,

y = 3x + 2

when x = 0

y = 3(0) + 2

y = 0 + 2

y = 2

(x,y) = (0,2)

when x = 1

y = 3(1) + 2

y = 3 + 2

y = 5

(x,y) = (1,5)

when x = 2

y = 3(2) + 2

y = 6 + 2

y = 8

(x,y) = (2,8)

Question 49.

y = 2x + 4

Answer:

Given,

y = 2x + 4

when x = 0

y = 2x + 4

y = 2(0) + 4

y = 0 + 4

y = 4

when x = 1

y = 2x + 4

y = 2(1) + 4

y = 2 + 4

y = 6

when x = 2

y = 2x + 4

y = 2(2) + 4

y = 4 + 4

y = 8

Question 50.

y = \(\frac{2}{3}\)x + 8

Answer:

Question 51.

y = \(\frac{1}{4}\)x + 6

Answer:

Question 52.

y = 2.5x + 12

Answer:

Question 53.

**MODELING REAL LIFE**

A cheese pizza costs $5. Additional toppings cost $1.50 each. Write and graph an equation that represents the total cost (in dollars) of a pizza.

Answer:

Let x be the total cost of pizza

let x be the number of toppings

Total cost equals the cost of cheese pizza plus the cost of additional toppings times the number of toppings

The equation would be x = 5 + 1.50t

Table & Graph:

Number of toppings Total cost, x = 5 + 1.50 t Ordered pairs (t, x)

1 6 (1, 6.50)

2 9 (2, 8)

3 9 (3, 9.50)

Question 54.

**MODELING REAL LIFE**

It costs $35 for a membership at a wholesale store. The monthly fee is $15. Write and graph an equation that represents the total cost (in dollars) of a membership.

Answer:

The equation is y = 35 + 25x

Table & Graph:

Number of months(x) Total cost, y = 35 + 25x Ordered pairs (t, x)

1 60 (1, 60)

2 85 (2, 85)

3 110 (3, 110)

Question 55.

**PROBLEM SOLVING**

The maximum size of a text message is 160 characters. A space counts as one character.

a. Write an equation that represents the number of remaining (unused) characters in a text message as you type.

b. Identify the independent and dependent variables.

c. How many characters remain in the message shown?

Answer:

x = the number of characters used

y = the number of characters unused

The equation would be y = 160 – x

The number of unused characters (y) depends on the number of used character (x)

The dependent variable is y

The Independent variable is x

Including space and punctuation, 15 characters were used

y = 160 – x

y = 160 – 15

y = 145

Question 56.

**CHOOSE TOOLS**

A car averages 60 miles per hour on a road trip. Use a graph to represent the relationship between the time and the distance traveled.

Answer:

**PRECISION** Write and graph an equation that represents the relationship between the time and the distance traveled.

Question 57.

Answer:

Question 58.

Answer:

Question 59.

Answer:

Question 60.

Answer:

**IDENTIFYING SOLUTIONS** Fill in the blank so that the ordered pair is a solution of the equation.

Question 61.

Answer:

y = 8x + 3

x = 1

y = 8(1) + 3

y = 11

Thus the ordered pair (1, 11)

Question 62.

Answer:

y = 12x + 2

y = 14

14 = 12x + 2

14 – 2 = 12x

12 = 12x

x = 1

Thus the ordered pair (1, 14)

Question 63.

Answer:

y = 9x + 4

y = 22

22 = 9x + 4

22 – 4 = 9x

9x = 18

x = 2

Question 64.

**DIG DEEPER!**

Can the dependent variable cause a change in the independent variable? Explain.

Answer:

Just like an independent variable, a dependent variable is exactly what it sounds like. It is something that depends on other factors.

Question 65.

**OPEN-ENDED**

Write an equation that has (3, 4) as a solution.

Answer:

Standard form linear equation

ax + by = c

When a, b and c are constants

We want to make two equations that

i. have that form

ii. do not have all the same solutions and

iii. (3, 4) is a solution to both

a(3) + b(4) = c

3a + 4b = c

Question 66.

**MODELING REAL LIFE**

You walk 5 city blocks in 12 minutes. How many city blocks can you walk in 2 hours?

Answer:

Given,

You walk 5 city blocks in 12 minutes.

12 min = 5 city

2 hours = 120 minutes

120 minutes = 300 minutes

Question 67.

**GEOMETRY**

How fast should the ant walk to go around the rectangle in 4 minutes?

Answer:

First find the perimeter of the rectangle

P = 2L + 2W

P = 2(16) + 2(12)

P = 32 + 24 = 56 in

r = d/t

r = 56/4

r = 14 in/min

Question 68.

**MODELING REAL LIFE**

To estimate how far you are from lightning (in miles), count the number of seconds between a lightning flash and the thunder that follows. Then divide the number of seconds by 5. Use two different methods to find the number of seconds between a lightning flash and the thunder that follows when a storm is 2.4 miles away.

Answer:

If you count the number of seconds between the flash of lightning and the sound of thunder, and then divide by 5, you’ll get the distance in miles to the lightning: 5 seconds = 1 mile, 15 seconds = 3 miles, 0 seconds = very close.

Question 69.

**REASONING**

The graph represents the cost c (in dollars) of buying n tickets to a baseball game.

a. Should the points be connected with a line to show all the solutions? Explain your reasoning.

b. Write an equation that represents the graph.

Answer: y = 5x + 0.5

### Equations Connecting Concepts

**Using the Problem-Solving Plan**

Question 1.

A tornado forms 12.25 miles from a weather station. It travels away from the station at an average speed of 440 yards per minute. How far from the station is the tornado after 30 minutes?

Understand the problem.

You know the initial distance between the tornado and the station, and the average speed the tornado is traveling away from the station. You are asked to determine how far the tornado is from the station after 30 minutes.

Make a plan.

First, convert the average speed to miles per minute. Then write an equation that represents the distance d (in miles) between the tornado and the station after t minutes. Use the equation to find the value of d when t = 30.

Solve and check.

Use the plan to solve the problem. Then check your solution.

Answer:

440 × 30 = 13200

Question 2.

You buy 96 cans of soup to donate to a food bank. The store manager discounts the cost of each case for a total discount of $40. Use an equation in two variables to find the discount for each case of soup. What is the total cost when each can of soup originally costs $1.20?

Answer:

Given,

You buy 96 cans of soup to donate to a food bank.

The store manager discounts the cost of each case for a total discount of $40.

1 case = 12 cans

x = 96 cans

96 = 12 × x

x = 96/12

x = 8

8 cases

8 × $40 = $320

8 × $1.20 = $9.6

Question 3.

The diagram shows the initial amount raised by an organization for cancer research. A business agrees to donate $2 for every $5 donated by the community during an additional fundraising event. Write an equation that represents the total amount raised (in dollars). How much money does the community need to donate for the organization to reach its fundraising goal?

Answer: 13,000 – 8000 = 5,000

**Performance Task**

Planning the Climb

At the beginning of this chapter, you watched a STEAM video called “Rock Climbing.” You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.

### Equations Chapter Review

**Review Vocabulary**

Write the definition and give an example of each vocabulary term.

**Graphic Organizers**

You can use an Example and Non-Example Chart to list examples and non-examples of a concept. Here is an Example and Non-Example Chart for the vocabulary term equation.

Choose and complete a graphic organizer to help you study the concept.

1. inverse operations

2. solving equations using addition or subtraction

3. solving equations using multiplication or division

4. equations in two variables

5. independent variables

6. dependent variables

**Chapter Self-Assessment**

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.

**6.1 Writing Equations in One Variable (pp. 245–250)**

Learning Target: Write equations in one variable and write equations that represent real-life problems.

**Write the word sentence as an equation.**

Question 1.

The product of a number m and 2 is 8.

Answer: m × 2 = 8

Explanation:

We have to write the word sentence in the equation.

The phrase product indicates ‘×’

The equation would be m × 2 = 8

Question 2.

6 less than a number t is 7.

Answer: 6 – t = 7

Explanation:

We have to write the word sentence in the equation.

The phrase less than indicates ‘-‘

The equation would be 6 – t = 7

Question 3.

A number m increased by 5 is 7.

Answer: m + 5 = 7

Explanation:

We have to write the word sentence in the equation.

The phrase increased indicates ‘+’

The equation would be m + 5 = 7

Question 4.

8 is the quotient of a number g and 3.

Answer: g ÷ 3 = 8

Explanation:

We have to write the word sentence in the equation.

The phrase quotient indicates ‘÷’

The equation would be g ÷ 3 = 8

Question 5.

The height of the 50-milliliter beaker is one-third the height of the 2000-milliliter beaker. Write an equation you can use to find the height (in centimeters) of the 2000-milliliter beaker.

Answer: y = 3x

Explanation:

Given,

The height of the 50-milliliter beaker is one-third the height of the 2000-milliliter beaker.

Let the height of 2000 ml beaker = x

Given,

Height of 50 ml beaker, y = 1/3 of x

The equation to find the height of the 2000 ml beaker will be

y = 3x

which means the height of the 2000 ml beaker is three times the height of the 500 ml beaker.

Therefore, the equation is y = 3x.

Question 6.

There are 16 teams in a basketball tournament. After two rounds, 12 teams are eliminated. Write and solve an equation to find the number of teams remaining after two rounds.

Answer:

Given,

There are 16 teams in a basketball tournament. After two rounds, 12 teams are eliminated.

x = 16

y = 12

Number of teams remaining after two rounds = z

z = x – y

z = 16 – 12

z = 4

Question 7.

Write an equation that has a solution of x = 8.

Answer: 4x = 32

Question 8.

Write a word sentence for the equation y + 3 = 5.

Answer: The sum of the numbers y and 3 is 5.

**6.2 Solving Equations Using Addition or Subtraction (pp. 251–258)**

Learning Target: Write and solve equations using addition or subtraction.

Question 9.

Tell whether x = 7 is a solution of x + 9 = 16.

Answer: Yes

Explanation:

Given the equation

x + 9 = 16

x = 16 – 9

x = 7

**Solve the equation. Check your solution.**

Question 10.

x – 1 = 8

Answer: 9

Explanation:

Given the equation

x – 1 = 8

x = 8 + 1

x = 9

Question 11.

m + 7 = 11

Answer: 4

Explanation:

Given the equation

m + 7 = 11

m = 11 – 7

m = 4

Question 12.

21 = p – 12

Answer: 33

Explanation:

Given the equation

21 = p – 12

p – 12 = 21

p = 21 + 12

p = 33

**Write the word sentence as an equation. Then solve the equation.**

Question 13.

5 more than a number x is 9.

Answer: 5 + x = 9

Explanation:

We have to write the word sentence as an equation

The phrase more than indicates ‘+’

Thus the equation would be 5 + x = 9

Question 14.

82 is the difference of a number b and 24.

Answer: b – 24 = 82

Explanation:

We have to write the word sentence as an equation

The phrase difference indicates ‘-‘

Thus the equation would be b – 24 = 82

Question 15.

A stuntman is running on the roof of a train. His combined speed is the sum of the speed of the train and his running speed. The combined speed is 73 miles per hour, and his running speed is 15 miles per hour. Find the speed of the train.

Answer:

Given,

A stuntman is running on the roof of a train. His combined speed is the sum of the speed of the train and his running speed.

The combined speed is 73 miles per hour, and his running speed is 15 miles per hour.

Speed of the train = ?

Z = x – y

z = 73 – 15

z = 58

Question 16.

Before swallowing a large rodent, a python weighs 152 pounds. After swallowing the rodent, the python weighs 164 pounds. Find the weight of the rodent.

Answer:

Given that,

Before swallowing a large rodent, a python weighs 152 pounds.

After swallowing the rodent, the python weighs 164 pounds.

164 – 152 = 12 pounds

**6.3 Solving Equations Using Multiplication or Division (pp. 259–264)**

Learning Target: Write and solve equations using multiplication or division.

**Solve the equation. Check your solution.**

Question 17.

6 . q = 54

Answer: 9

Explanation:

Given the equation

6 . q = 54

q = 54/6

q = 9

Question 18.

k ÷ 3 = 21

Answer: 63

Explanation:

Given the equation

k ÷ 3 = 21

k = 21 × 3

k = 63

Question 19.

\(\frac{5}{7}\)a = 25

Answer: 35

Explanation:

Given the equation

\(\frac{5}{7}\)a = 25

5a = 7 × 25

a = 7 × 5

a = 35

Question 20.

The weight of an object on the Moon is about 16.5% of its weight on Earth. The weight of an astronaut on the Moon is 24.75 pounds. How much does the astronaut weigh on Earth?

Answer: 150 pounds

Explanation:

Given,

The weight of an object on the Moon is about 16.5% of its weight on Earth.

The weight of an astronaut on the Moon is 24.75 pounds.

Let the astronaut weight on Earth be represented by x.

Based on the information given in the question, thus can be formed into an equation as:

16.5% of x = 24.75

16.5% × x = 24.75

16.5/100 × x = 24.75

0.165x = 24.75

x = 24.75/0.165

x = 150 pounds

The astronaut weighs 150 pounds on Earth.

Question 21.

Write an equation that can be solved using multiplication and has a solution of x = 12.

Answer: 3x = 36

Question 22.

At a farmers’ market, you buy 4 pounds of tomatoes and 2 pounds of sweet potatoes. You spend 80% of the money in your wallet. How much money is in your wallet before you pay?

Answer: The money in your wallet before you pay is 20 dollars

Explanation:

Cost of 1 pound of tomato = 3 dollars

Therefore,

Cost of 4 pound of tomato = 4 x 3 = 12 dollars

Cost of 4 pound of tomato = 12 dollars

Cost of 1 pound of sweet potatoes = 2 dollars

Therefore,

Cost of 2 pound of sweet potatoes = 2 x 2 = 4 dollars

Cost of 2 pounds of sweet potatoes = 4 dollars

The combined cost spend at the market is:

cost spend at market = Cost of 4 pound of tomato + Cost of 2 pound of sweet potatoes

cost spend at market = 12 + 4 = 16 dollars

You spent 80% of the money in your wallet

Therefore, 80% of the money in your wallet is equal to 16 dollars

Let x be the money in your wallet

Then, we get

80 % of x = 16

80/100 × x = 16

0.8 x = 16

x = 16/0.8

x = 20

Thus money in your wallet before you pay is $20.

**6.4 Writing Equations in Two Variables (pp. 265-272)**

Learning Target: Write equations in two variables and analyze the relationship between the two quantities.

**Tell whether the ordered pair is a solution of the equation.**

Question 23.

y = 3x + 1; (2, 7)

Answer:

Given the equation

x = 2

y = 7

7 = 3(2) + 1

7 = 6 + 1

7 = 7

Yes, it is the solution of the equation.

Question 24.

y = 7x – 4; (4, 22)

Answer:

Given the equation

x = 4

y = 22

22 = 7(4) – 4

22 = 28 – 4

22 ≠ 24

No, it is not the solution of the equation.

Question 25.

The equation E = 360m represents the kinetic energy E (in joules) of a roller-coaster car with a mass of m kilograms. Identify the independent and dependent variables.

Answer: E is the dependent variable

m is the independent variable

**Graph the equation.**

Question 26.

y = x + 1

Answer:

Given,

y = x + 1

when x = 0

y = 0 + 1

y = 1

(x, y) = (0, 1)

when x = 1

y = 1 + 1

y = 2

(x, y) = (1, 2)

when x = 2

y = 2 + 1

y = 3

(x, y) = (2, 3)

Question 27.

y = 7x

Answer:

Question 28.

y = 4x + 3

Answer:

Question 29.

y = \(\frac{1}{2}\)x + 5

Answer:

Given,

y = \(\frac{1}{2}\)x + 5

when x = 0

y = \(\frac{1}{2}\)0+ 5

y = 5

when x = 0

y = \(\frac{1}{2}\)1+ 5

y = 5\(\frac{1}{2}\)

Question 30.

A taxi ride costs $3 plus $2.50 per mile. Write and graph an equation that represents the total cost (in dollars) of a taxi ride. What is the total cost of a five-mile taxi ride?

Answer:

Given,

A taxi ride costs $3 plus $2.50 per mile.

5 × 2.50 = $25.50

Question 31.

Write and graph an equation that represents the total cost (in dollars) of renting the bounce house. How much does it cost to rent the bounce house for 6 hours?

Answer:

C= $25 x 6 = $150

25×6=150+100=250

Question 32.

A car averages 50 miles per hour on a trip. Write and graph an equation that represents the relationship between the time and the distance traveled. How long does it take the car to travel 525 miles?

Answer:

Given,

A car averages 50 miles per hour on a trip.

50 miles – 1 hour

525 miles – x

50 × x = 525

x = 525/50

x = 10.50 hours

Thus it takes 10.5 hours to travel 525 miles.

### Equations Practice Test

Question 1.

Write “7 times a number is 84” as an equation.

Answer: 7 × n = 84

Explanation:

We have to write the word sentence into the equation

The phrase times indicates ‘×’

Thus the equation would be 7 × n = 84

Solve the equation. Check your solution.

Question 2.

15 = 7 + b

Answer: b = 8

Explanation:

Given,

15 = 7 + b

b = 15 – 7

b = 8

Question 3.

v – 6 = 16

Answer: v = 22

Explanation:

Given,

v – 6 = 16

v = 16 + 6

v = 22

Question 4.

5x = 70

Answer: x = 14

Explanation:

Given,

5x = 70

x = 70/5

x = 14

Question 5.

\(\frac{6m}{7}\) = 30

Answer:

Given,

\(\frac{6m}{7}\) = 30

6m = 30 × 7

6m = 210

m = 210 ÷ 6

m = 35

Question 6.

Tell whether (3, 27) is a solution of y = 9x

Answer: solution

Explanation:

Given,

y = 9x

x = 3

y = 27

27 = 9(3)

27 = 27

Thus the ordered pair is a solution.

Question 7.

Tell whether (8, 36) is a solution of y = 4x + 2.

Answer: not a solution

Explanation:

Given,

y = 4x + 2.

x = 8

y = 36

36 = 4(8) + 2

36 = 32 + 2

36 ≠ 34

Question 8.

The drawbridge shown consists of two identical sections that open to allow boats to pass. Write s an equation you can use to find the length (in feet) of each section of the drawbridge.

Answer: 2s = 366ft

Question 9.

Each ticket to a school dance is $4. The total amount collected in ticket sales is $332. Find the number of students attending the dance.

Answer:

Given,

Each ticket to a school dance is $4.

The total amount collected in ticket sales is $332.

The equation would be

4s = 332

s = 83

Question 10.

A soccer team sells T-shirts for a fundraiser. The company that makes the T-shirts charges $10 per shirt plus a $20 shipping fee per order.

a. Write and graph an equation that represents the total cost (in dollars) of ordering the shirts.

Answer:

For this case, the first thing we must do is define variables:

c = total cost

x = x number of shirts.

The equation that adapts to the problem is:

c (x) = 10x + 20

b. Choose an ordered pair that lies on your graph in part(a). Interpret it in the context of the problem.

Answer:

Let’s choose the next ordered pair:

(x, c (x)) = (0, 20)

We verify that it is in the graph:

c (20) = 10 (0) + 20

c (20) = 20 (yes, it belongs to the graph).

In the context of the problem, this point means that the cost per shipment is $ 20

Question 11.

You hand in 2 homework pages to your teacher. Your teacher now has 32 homework pages to grade. Find the number of homework pages that your teacher originally had to grade.

Answer:

Given that,

You hand in 2 homework pages to your teacher.

Your teacher now has 32 homework pages to grade.

32 – 2 = 30

Question 12.

Write an equation that represents the total cost (in dollars) of the meal shown with a tip that is a percent of the check total. What is the total cost of the meal when the tip is 15%?

Answer: $41.40

### Equations Cumulative Practice

Question 1.

You buy roses at a flower shop for $3 each. How many roses can you buy with $27?

A. 9

B. 10

C. 24

D. 81

Answer: 9

Explanation:

given,

You buy roses at a flower shop for $3 each.

27/3 = 9

Thus you can buy 9 roses with $27.

Thus the correct answer is option A.

Question 2.

You are making identical fruit baskets using 16 apples, 24 pears, and 32 bananas. What is the greatest number of baskets you can make using all of the fruit?

F. 2

G. 4

H. 8

I. 16

Answer: 8

Explanation:

Given,

You are making identical fruit baskets using 16 apples, 24 pears, and 32 bananas.

8 baskets

MULTIPLES OF 16, 24, and, 32

16: 1, 2, 4, 8, 16

24: 1, 2, 3, 4, 6, 8, 12, 24

32: 1, 2, 4, 8, 16, 32

Question 3.

Which equation represents the word sentence?

A. 18 – 5 = 9 – y

B. 18 + 5 = 9 – y

C. 18 + 5 = y – 9

D. 18 – 5 = y – 9

Answer: 18 + 5 = 9 – y

Explanation:

The suitable equation for the above word sentence is

18 + 5 = 9 – y

Thus the correct answer is option B.

Question 4.

The tape diagram shows the ratio of tickets sold by you and your friend. How many more tickets did you sell than your friend?

F. 6

G. 12

H. 18

I. 30

Answer: 6

Explanation:

Each rectangle = 6

6 × 5 = 30

6 × 2 = 12

30 + 12 = 42

Thus the correct answer is option A.

Question 5.

What is the value of x that makes the equation true?

59 + x = 112

Answer:

Given the equation

59 + x = 112

x = 112 – 59

x = 53

Thus the value of x that makes the equation true is 53

Question 6.

The steps your friend took to divide two mixed numbers are shown.

What should your friend change in order to divide the two mixed numbers correctly?

A. Find a common denominator of 5 and 2.

B. Multiply by the reciprocal of \(\frac{18}{5}\).

C. Multiply by the reciprocal of \(\frac{3}{2}\).

D. Rename 3\(\frac{3}{5}\) as 2\(\frac{8}{5}\).

Answer: Multiply by the reciprocal of \(\frac{3}{2}\).

Question 7.

A company ordering parts receives a charge of $25 for shipping and handling plus cp$20 per part. Which equation represents the cost (in dollars) of ordering parts?

F. c = 25 + 20p

G. c = 20 + 25p

H. p = 25 + 20c

I. p = 20 + 25c

Answer: c = 25 + 20p

Question 8.

Which property is illustrated by the statement?

5(a + 6) = 5(a) + 5(6)

A. Associative Property of Multiplication

B. Commutative Property of Multiplication

C. Commutative Property of Addition

D. Distributive Property

Answer: Distributive Property

Question 9.

What is the value of the expression?

46.8 ÷ 0.156

Answer:

Divide the two decimal numbers

we get the answer

300

Question 10.

In the mural below, the squares that are painted red are marked with the letter R.

What percent of the mural is painted red?

F. 24%

G. 25%

H. 48%

I. 50%

Answer: 48%

Question 11.

Which expression is equivalent to 28x + 70?

A. 14 (2x + 5)

B. 14 (5x + 2)

C. 2 (14x + 5)

D. 14 (7x)

Answer: 14 (2x + 5)

Explanation:

28x + 70

Taking 14 as the common factor

14(2x + 5)

Thus the correct answer is option A.

Question 12.

What is the first step in evaluating the expression?

3 . (5 + 2)^{2} ÷ 7

F. Multiply 3 and 5.

G. Add 5 and 2

H. Evaluate 5^{2}.

I. Evaluate 2^{2}.

Answer: G. Add 5 and 2

Question 13.

Jeff wants to save $4000 to buy a used car. He has already saved $850. He plans to save an additional $150 each week.

Part A Write and solve an equation to represent the number of weeks remaining until he can afford the car.

Jeff saves $150 per week by saving \(\frac{3}{4}\) of what he earns at his job each week.

He works 20 hours per week.

Part B Write an equation to represent the amount per hour that Jeff must earn to save $150 per week. Explain your reasoning.

Part C What is the amount per hour that Jeff must earn? Show your work and explain your reasoning.

Answer: 21 weeks

Explanation:

150 × 21 = 3150

3150 + 850 = 4000

*Conclusion:*

We put all our efforts and experience to prepare Big Ideas Math Book 6th Grade Answer Key Chapter 6 Equations pdf. Hope you are satisfied with the given data and information regarding Big Ideas Math Book 6th Grade Answer Key Chapter 6 Equations. If you have any kind of doubts, clarify with us here. We wish all the very best for all the aspirants preparing for the exam.