Eureka Math Grade 6 Module 2 Lesson 8 Answer Key

Engage NY Eureka Math 6th Grade Module 2 Lesson 8 Answer Key

Eureka Math Grade 6 Module 2 Lesson 8 Example Answer Key

Example 1: Introduction to Calculating the Quotient of a Mixed Number and a Fraction

a. Carll has 4\(\frac{1}{2}\) walls left to paint in order for all the bedrooms in her house to have the same color paint.
However, she has used almost all of her paint and only has \(\frac{5}{6}\) of a gallon left.
How much paint can she use on each wall in order to have enough to paint the remaining wails?
Answer:
Write the expression: \(\frac{5}{6}\) ÷ 4\(\frac{1}{2}\)
Convert into a fraction: \(\frac{9}{2}\)
Divide fractions: \(\frac{5}{6} \div \frac{9}{2}=\frac{5}{6} \times \frac{2}{9}=\frac{10}{54} \text { or } \frac{5}{27}\)
Carli can use \(\frac{5}{27}\) of a gallon paint on each of the remaining walls.

b. Calculate the quoitent.
\(\frac{2}{5} \div 3 \frac{4}{7}\)
Answer:
Convert into a fraction: \(\frac{25}{7}\)
Divide fractions: \(\frac{2}{5} \div \frac{25}{7}=\frac{2}{5} \times \frac{7}{25}=\frac{14}{125}\)

Eureka Math Grade 6 Module 2 Lesson 8 Exercise Answer Key

Exercise 1.
Show your work for the memory game in the boxes provided below.
Eureka Math Grade 6 Module 2 Lesson 8 Exercise Answer Key 1
Answer:
Eureka Math Grade 6 Module 2 Lesson 8 Exercise Answer Key 2

Eureka Math Grade 6 Module 2 Lesson 8 Problem Set Answer Key

Calculate each quoitent.

Question 1.
\(\frac{2}{5} \div 3 \frac{1}{10}\)
Answer:
\(\frac{2}{5} \div \frac{31}{10}=\frac{2}{5} \times \frac{10}{31}=\frac{20}{155} \text { or } \frac{4}{31}\)

Question 2.
\(4 \frac{1}{3} \div \frac{4}{7}\)
Answer:
\(\frac{13}{3} \div \frac{4}{7}=\frac{13}{3} \times \frac{7}{4}=\frac{91}{12} \text { or } 7 \frac{7}{12}\)

Question 3.
\(3 \frac{1}{6} \div \frac{9}{10}\)
Answer:
\(\frac{19}{6} \div \frac{9}{10}=\frac{19}{6} \times \frac{10}{9}=\frac{190}{54} \text { or } \frac{95}{27} \text { or } 3 \frac{28}{54} \text { or } 3 \frac{14}{27}\)

Question 4.
\(\frac{5}{8} \div 2 \frac{7}{12}\)
Answer:
\(\frac{5}{8} \div \frac{31}{12}=\frac{5}{8} \times \frac{12}{31}=\frac{60}{248} \text { or } \frac{15}{62}\)

Eureka Math Grade 6 Module 2 Lesson 8 Exit Ticket Answer Key

Calculate the quoitent.

Question 1.
\(\frac{3}{4} \div 5 \frac{1}{5}\)
Answer:
\(\frac{3}{4} \div 5 \frac{1}{5}=\frac{3}{4} \div \frac{26}{5}=\frac{3}{4} \times \frac{5}{26}=\frac{15}{104}\)

Question 2.
\(\frac{3}{7} \div 2 \frac{1}{2}\)
Answer:
\(\frac{3}{7} \div 2 \frac{1}{2}=\frac{3}{7} \div \frac{5}{2}=\frac{3}{7} \times \frac{2}{5}=\frac{6}{35}\)

Question 3.
\(\frac{5}{8} \div 6 \frac{5}{6}\)
Answer:
\(\frac{5}{8} \div 6 \frac{5}{6}=\frac{5}{8} \div \frac{41}{6}=\frac{5}{8} \times \frac{6}{41}=\frac{30}{328} \text { or } \frac{15}{164}\)

Question 4.
\(\frac{5}{8} \div 8 \frac{3}{10}\)
Answer:
\(\frac{5}{8} \div 8 \frac{3}{10}=\frac{5}{8} \div \frac{83}{10}=\frac{5}{8} \times \frac{10}{83}=\frac{50}{664} \text { or } \frac{25}{332}\)

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